Reasoning
Reasoning #2

You have 8 identical-looking balls. One is slightly heavier than the rest. Using a balance scale, what is the minimum number of weighings needed to guarantee you find the heavy ball? Explain your strategy.

9 models responded

high10.0

Judge: Correct answer (2 weighings) with a complete, thorough strategy covering all branches. Explains the information-theoretic lower bound (3^W >= 8), details the 3-3-2 split, and walks through every outcome for both weighings. Exceptionally clear presentation with all cases covered.

The minimum number of weighings needed to guarantee you find the heavy ball is **2**. Here's the strategy: **Understanding the Balance Scale:** A balance scale has three possible outcomes for each w...
gemini/gemini-2.5-flash · 2026-03-02
DeepSeek R1DeepSeek
high9.6

Judge: Correct answer (2 weighings) with a complete strategy covering all branches: 3v3 with 2 aside, then second weighing handles both the group-of-3 and group-of-2 cases. Includes the information-theoretic justification (3^2=9 >= 8). The strategy is clearly explained with all decision paths enumerated. The explanation is concise and elegant.

The minimum number of weighings needed to guarantee finding the heavier ball among 8 identical-looking balls is **2**. ### Strategy: 1. **First weighing**: Place 3 balls on each side of the balance s...
deepseek/deepseek-reasoner · 2026-03-02
o4-miniOpenAI
high9.4

Judge: Correct answer of 2 weighings with a complete strategy covering all branches. Includes the information-theoretic bound (3^k >= 8) as justification for why 1 weighing is insufficient. The strategy clearly covers both outcomes of the first weighing (balanced vs unbalanced) and all sub-cases of the second weighing. Exceptionally clear presentation.

You only need 2 weighings. Here’s why and how: 1) Information bound. A balance scale has three possible outcomes each time (left pan heavy / right pan heavy / balance). With k weighings you can di...
openai/o4-mini · 2026-03-02
GPT-4oOpenAI
high9.1

Judge: Correct answer of 2 weighings with a complete strategy covering all decision branches. The 3-3-2 split is optimal and all outcomes are traced. Minor gap: doesn't explicitly argue why 1 weighing is insufficient.

To find the one heavier ball among 8 identical-looking balls using a balance scale, you can do it in just 2 weighings. Here's the strategy: 1. **First Weighing:** - Divide the 8 balls into three g...
openai/gpt-4o · 2026-03-01
Claude OpusAnthropic
high9.0

Judge: Correct answer (2 weighings) with a complete, well-explained strategy. Uses information-theoretic reasoning (3 outcomes per weighing, 3^2=9 >= 8) to establish the lower bound, then provides the constructive strategy (3-3-2 split). Covers all branches including the 2-suspect case. Clear formatting and logical flow. A near-perfect response.

I need to find the minimum number of weighings to guarantee finding the heavy ball among 8 identical-looking balls. Let me work through this systematically. With a balance scale, each weighing gives...
anthropic/claude-opus-4-20250514 · 2026-03-01
Claude HaikuAnthropic
high8.8

Judge: Correct answer (2 weighings) with a complete strategy covering all branches. The 3-3-2 split is optimal, and both outcomes (3 suspects and 2 suspects) are explained. Includes the information-theoretic justification (3^2=9 > 8). Well-structured and clear.

# Finding the Heavy Ball: Minimum Weighings ## Answer: **2 weighings** ## Strategy **First Weighing: Divide into thirds** - Split 8 balls into three groups: 3, 3, and 2 balls - Weigh the two groups...
anthropic/claude-haiku-4-5-20251001 · 2026-03-01
Claude SonnetAnthropic
high8.6

Judge: Correct answer (2 weighings) with a complete strategy covering all branches. The divide-into-thirds approach is optimal and well-explained. Covers all three outcomes of the first weighing and all sub-cases of the second. The information theory justification (3^2 = 9 >= 8) is a nice bonus that explains why 2 is sufficient and 1 is not. Clear, well-structured presentation.

I need to find the minimum number of weighings to guarantee finding the heavy ball among 8 identical-looking balls. Let me think about this systematically using the concept of information theory and ...
anthropic/claude-sonnet-4-20250514 · 2026-03-01
Phi-4Microsoft
high8.4

Judge: Correct answer (2 weighings) with a complete strategy covering all branches. The 3-3-2 split is the standard optimal approach. All cases are covered: balanced first weighing leads to comparing the 2-ball group, unbalanced leads to comparing 2 of 3 from the heavy group. Clear formatting with step-by-step analysis of each branch.

To find the single heavier ball among the eight using a balance scale with the minimum number of weighings, you can follow this strategy: ### Step-by-Step Strategy 1. **First Weighing:** - Divide...
ollama/phi4 · 2026-03-01
medium5.4

Judge: Correct answer of 2 weighings, but the strategy explanation has gaps. The first weighing (3 vs 3) is correctly described, but Step 5 and beyond are vague about the second weighing -- it says 'take half of those identified balls' without explicitly walking through both branches (3 balls case: weigh 1 vs 1; 2 remaining balls case: weigh 1 vs 1). The 'remaining 4' scenario from a balanced first weighing is wrong (should be 2 remaining, not 4).

## Step 1: Determine the goal The goal is to find the heaviest ball among 8 identical-looking balls with the least number of weighings on a balance scale. ## Step 2: Understand the balance scale's fu...
ollama/llama3.1:8b · 2026-03-01