Reasoning
Reasoning #4

In a round-robin tournament with 6 players, each player plays every other player exactly once. A win is worth 2 points, a draw is 1 point each, and a loss is 0 points. After the tournament: Player A has 10 points, Player B has 8 points, and Player C has 6 points. Players D, E, and F each have the same score. What score do D, E, and F each have? Show your reasoning.

14 models responded

GPT-4oOpenAI
high10.0

Judge: Correct answer of 2 points each with elegant reasoning: calculates total games via C(6,2)=15, derives total points as 30, subtracts known scores (24), and divides remainder equally. Clean, complete, no gaps.

In a round-robin tournament with 6 players, each player plays every other player exactly once. This means each player plays 5 matches. There are \(\binom{6}{2} = 15\) total matches in the tournament. ...
openai/gpt-4o · 2026-03-01
high10.0
Run 1 of 2

Judge: Correct answer (2 points each) with elegant, complete mathematical reasoning. Correctly calculates total games (15), total points (30), subtracts known scores (24), and divides remaining (6) by 3. Clean step-by-step presentation that's easy to follow.

Here's how to determine the score for players D, E, and F: 1. Calculate the total number of games played: In a round-robin tournament with n players, the number of games is n * (n - 1) / 2. ...
gemini/gemini-2.5-flash · 2026-03-02avg: 10.0
high10.0

Judge: Correct answer (2 each) via the standard 15 games x 2 = 30 total, minus 24, divided by 3. Concise, sound, and clearly laid out.

Each player plays 5 games, so the total number of points in the tournament is fixed. • In a win/loss game, the total points awarded are \(2\). • In a draw game, the total points awarded are also \(2\...
openai/gpt-5.4-mini · 2026-06-10
GPT-5.5OpenAI
high10.0

Judge: Correct answer of 2 points each via the clean total-points argument (15 games x 2 = 30, minus 24, divided by 3). Mathematical reasoning is fully shown and elegant. Clear formatting.

There are \(\binom{6}{2} = 15\) games total. Each game always awards exactly 2 total points: • win/loss: \(2+0=2\) • draw: \(1+1=2\) So the total number of points awarded in the tournament is: \[ ...
openai/gpt-5.5 · 2026-06-10
DeepSeek V4DeepSeek
high10.0

Judge: Correct answer of 2 points each with complete, sound reasoning (total points = 30, remaining = 6, split three ways). Math is clearly shown, satisfying the hard constraint. Well-structured.

Each match in the tournament awards a total of 2 points (either 2 for a win and 0 for a loss, or 1 each for a draw). With 6 players, there are \(\binom{6}{2} = 15\) matches. Therefore, the total point...
deepseek/deepseek-v4-pro · 2026-06-10
GPT-5.4OpenAI
high10.0

Judge: Correct answer of 2 points each, derived via the elegant invariant that 15 matches always distribute exactly 30 points: 30 - 24 = 6, split equally three ways. The math is shown step by step, satisfying the hard constraint, and the presentation is crisp. This is exactly the reasoning the rubric's top band describes.

There are \(\binom{6}{2} = 15\) matches total. Each match gives out: • \(2\) total points if someone wins • \(2\) total points if it’s a draw (\(1+1\)) So every match contributes 2 points total, me...
openai/gpt-5.4 · 2026-06-11
Claude FableAnthropic
high10.0

Judge: Correct answer (2 points each) derived cleanly: 15 games, 30 total points, 30 - 24 = 6, 6/3 = 2. I verified the math and the achievability construction (D/E/F drawing among themselves) is valid. Elegant, complete, and clearly shown.

Setting Up With 6 players in a round-robin, the number of games is: $$\binom{6}{2} = 15 \text{ games}$$ Key fact: Every game distributes exactly 2 points (either 2+0 for a win/loss, or 1+1 for a dra...
anthropic/claude-fable-5 · 2026-06-11
DeepSeek R1DeepSeek
high9.8

Judge: Correct answer (2 points each) with elegant mathematical reasoning. Correctly computes total games (C(6,2)=15), total points (30), sets up the equation 24+3x=30, solves for x=2. Then goes further to verify feasibility by constructing a valid tournament outcome (A beats all, B beats all except A, C beats D/E/F, then D/E/F play among themselves). This verification step elevates the answer from good to excellent.

In a round-robin tournament with 6 players, each player plays every other player exactly once. A win is worth 2 points, a draw is worth 1 point each, and a loss is worth 0 points. The total number of ...
deepseek/deepseek-reasoner · 2026-03-02
o4-miniOpenAI
high9.6

Judge: Correct answer of 2 points each with elegant reasoning. First establishes total points (15 games x 2 = 30), then subtracts known scores to get D+E+F = 6, dividing by 3. Then goes further to verify the construction: A won all 5, B won 4 (lost to A), C won 3 (lost to A and B), and D/E/F drew all their matches among themselves. Complete and rigorous.

First note that with 6 players there are C(6,2)=15 games, and each game hands out exactly 2 points total (2–0 for a decisive result, or 1–1 for a draw). So the grand total of all players’ points is ...
openai/o4-mini · 2026-03-02
Claude OpusAnthropic
high9.2
Run 1 of 2

Judge: Correct answer (2 points each) with elegant reasoning. Correctly computes total games (C(6,2)=15), total points (30), then solves the simple equation. Verification step confirms the answer is within valid bounds. Clean mathematical presentation. Shows reasoning as requested.

I need to find the scores of players D, E, and F in a round-robin tournament. First, let me establish the basic facts: • 6 players total • Each player plays every other player exactly once • Win = 2 ...
anthropic/claude-opus-4-20250514 · 2026-03-01avg: 9.6
Claude HaikuAnthropic
high9.0
Run 1 of 2

Judge: Correct answer (2 points each) with elegant reasoning. Properly calculates total games (15), total points (30), sets up the equation, solves cleanly. Includes verification step. The mathematical presentation is crisp and well-structured.

Solution Setting Up the Problem In a round-robin tournament with 6 players: • Each player plays 5 games (one against each other player) • Total number of games: $\binom{6}{2} = 15$ games Calculatin...
anthropic/claude-haiku-4-5-20251001 · 2026-03-01avg: 9.5
Phi-4Microsoft
high9.0
Run 1 of 2

Judge: Correct answer (2 points each) with elegant reasoning. Cleanly calculates total games (C(6,2)=15), total points (15x2=30), subtracts known scores (24), and divides remainder (6) by 3 players. The mathematical reasoning is airtight and clearly presented with proper notation.

In a round-robin tournament with 6 players, each player plays every other player exactly once. This means there are a total of \(\binom{6}{2} = 15\) games played in the tournament. Each game results ...
ollama/phi4 · 2026-03-01avg: 9.5
Claude SonnetAnthropic
high8.4
Run 1 of 2

Judge: Correct answer (2 points each) with elegant reasoning. Immediately identifies the key insight: each game distributes exactly 2 total points, 15 games = 30 total points, solve for x. The algebra is clean and the verification step adds confidence. Also checks that the score is achievable (1 win + 3 losses or 2 draws + 3 losses), though the response is truncated before completing that check.

I need to find the score that players D, E, and F each have. Let me start by understanding the tournament structure and point system. Tournament Structure: • 6 players total • Each player plays ever...
anthropic/claude-sonnet-4-20250514 · 2026-03-01avg: 9.2
high2.4
Run 1 of 2

Judge: Response is truncated before reaching an answer. Sets up the problem correctly (15 games, known scores sum to 24) but never completes the calculation. The reasoning starts going off track in Step 5-6 with confused discussion of 'remaining points' and incorrect assertion that Player A 'must have won all his matches' (10 points from 5 games = 5 wins is correct, but the logic trail is abandoned mid-thought).

Step 1: Determine the total number of games played in a round-robin tournament with 6 players. In a round-robin tournament where every player plays against every other player once, we can use the form...
ollama/llama3.1:8b · 2026-03-01avg: 4.9